" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
|BC|²=(3-5)²+(3-2)²=4+1=5
|AC|²=(3-2)²+(3-1)²=1+4=5
Z twiedzenia odwrotnego do Tw. Pitagorasa:
jezeli |BC|²+|AC|²=|AB|², to trojkat ABC jest prostokatny.
q.e.d.
a=√5
b=√5
P=1/2*√5*√5=1/2*5=2,5