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kraw,boczna b=a
wysokosc podstawy h=a√3/2 to 2/3h=2/3·a√3/2=a√3/3
z pitagorasa(
a√3/3)²+H²=b²
3a²/9+H²=a²
1/3 a²+H²=a²
H²=a²-1/3 a²
H²=2/3 a²
H=a√(2/3)=a√2/√3=a(√2·√3)/3=a√6/3 --->wysokosc bryly
sinα=H/b=(a√6/3)/a=√6/3