dany jest ciąg arytmetyczny an w którym i . Drugi wyraz tego ciągu jest równy?
S₁=a₁=6
S₃=a₁ + a₁+r + a₁ + 2r
24=3a₁+3r /:3
8 = a₁ + r
8 = 6 + r
r=2
a₂ = a₁ + r = 6 + 2 = 8
a₁ = 6
S₃ = (2 * a₁ + 2*r)*3 / 2
24 = (36 + 6r)/2
24 = 18 + 3r
3r = 6
r = 2
a₂ = 8
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S₁=a₁=6
S₃=a₁ + a₁+r + a₁ + 2r
24=3a₁+3r /:3
8 = a₁ + r
8 = 6 + r
r=2
a₂ = a₁ + r = 6 + 2 = 8
a₁ = 6
S₃ = (2 * a₁ + 2*r)*3 / 2
24 = (36 + 6r)/2
24 = 18 + 3r
3r = 6
r = 2
a₂ = 8