Question

Dane są wielomiany p(x)=3x2-1 i W(x)=x+2

Znajdź P(1 + pierwiastek z 2 ) i 2(W(x))2 - 3 P(x)

Answer 1

*-druga potęga

^-pierwiastek drugiego stopnia

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p(x)=3x2-1

W(x)=x+2

 

p(x) = 3(1+^2)* - 1 = 3 (1+2^2 + 2) - 1 = 8 + 6^2

 

W(x)=x+2 = 3 +2^2 + 2 = 5 + 2^2

 

2w* - 3P =

 

2(5 + 2^2)* - 3 (8 + 6^2)=

2(25+8+20^2) -24 - 18^2=

66 +40^2 -24 -18^2= 22^2 +42

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