Odpowiedź:
[tex]\displaystyle A(3,\sqrt{2} )\quad B(1,-\sqrt{2} )\\A(x_1,y_1)\quad B(x_2,y_2_)\\y=ax+b\\a=\frac{y_2-y_1}{x_2-x_1} \\a=\frac{-\sqrt{2}-\sqrt{2} }{1-3} =\frac{-2\sqrt{2} }{-2} =\sqrt{2}[/tex]
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Odpowiedź:
[tex]\displaystyle A(3,\sqrt{2} )\quad B(1,-\sqrt{2} )\\A(x_1,y_1)\quad B(x_2,y_2_)\\y=ax+b\\a=\frac{y_2-y_1}{x_2-x_1} \\a=\frac{-\sqrt{2}-\sqrt{2} }{1-3} =\frac{-2\sqrt{2} }{-2} =\sqrt{2}[/tex]