Dane są liczby y-odwrotność liczby x ,z-liczba przeciwna do x , oblicz y i z . ;) POZDRAWIAM .
y=1/(3√2-2)=(3√2+2)/[(3√2-2)(3√2+2)]=(3√2+2)/(18-4)=(3√2+2)/14
z=-(3√2-2)=2-3√2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
y=1/(3√2-2)=(3√2+2)/[(3√2-2)(3√2+2)]=(3√2+2)/(18-4)=(3√2+2)/14
z=-(3√2-2)=2-3√2