Dane są liczby a=√6+√5 oraz b= 1 dzielone na √6-√5. Zatem
a=b
a>b
a<b
a+b=o ???
zatem a=b
a=√6+√5
b=1/(√6-√5)=(√6+√5)/(√6+√5)(√6-√5)=(√6+√5)/6-5=√6+√5
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zatem a=b
a=√6+√5
b=1/(√6-√5)=(√6+√5)/(√6+√5)(√6-√5)=(√6+√5)/6-5=√6+√5
a=b