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a)(a+2ab+b)-(a-2ab)+b=
a+2ab+b-a+2ab+b = 4ab+2b=2b(2a+1)
b)(ay-3a*5y-5⅔)-(4ay-3⅔)=
ay-15ay-5⅔-4ay+3⅔= -18ay-2
c)-(b²-2b+5)+b+3b-b²=
-b²+2b-5+b+3b-b²= -2b²+6b-5
d)5a²-2a²-(a-a²)-(12a-4a²)=
5a²-2a-a+a²-12a+4a²= 10a²-15a= 5a(2a-3)
2.Doprowadź wyrażenie algebraiczne do najprostszej postaci:
a)(a+2s)-½(a-2s)= a+2s-1/2a+s= ½a+3s
b)3(3s+2f)-2(2s+f)= 9s+6f-4s-2f=5s+4f
c)2x(a-b)+5(ax-bx)= 2ax-2bx+5ax-5bx=7ax-7bx =7x(a-b)
d)7(ax-2)-4a(x-2)+2(ax+2)= 7ax-14-4ax+8a+2ax+4=5ax+8a-10
e)2x(x+2)-(x²+2x)-4= 2x²+4x-x²-2x-4=x²+2x-4
a.(a+2ab+b)-(a-ab)+b= a+2ab+b-a+2b+b= 2ab+4b
b.(ay-3a*5y-5⅔)-(4ay-3⅔)= ay-3a*5y-5⅔- 4ay+3⅔= 3ay-15ay-2⅔=-12ay-2⅔
c.-(b²-2b+5)+b+3b-b²=-b²+2b-5+b+3b-b²= -2b²+6b+5
d.5a²-2a²-(a-a²)-(12a-4a²)=3a²-a+a²-12a+4a²= 8a²-13a
2.
a)(a+2s)-½(a-2s)=a+2s-½a-s=a+s
b)3(3s+2f)-2(2s+f)=9s+6f-4s+4f= 5s+11f
c)2x(a-b)+5(ax-bx)=2xa-2xb+5ax-5bx= 3ax-7bx
d)7(ax-2)-4a(x-2)+2(ax+2)=7ax-14-4ax+8a+2ax+4=9ax-10+8a
e)2x(x+2)-(x²+2x)-4= 2x²+4x-x²-2x-4= x²+2x-4