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(1-5x)(x+2)+(5x-1)(8-2x). Krok po kroku !
(1-5x)(x+2)+(5x-1)(8-2x)=
(x+2-5x²-10x)+(40x-10x²-8+2x)=
x+2-5x²-10x+40x-10x²-8+2x=
-15x²+33x-6=
-3(5x²-11x+2)
5x²-11x+2=0
Δ=121-40=81
√Δ=9
x₁=(11-9)/(10)=2/10=0,2
x₂=(11+9)/(10)=20/10=2
-3(5x²-11x+2)= -3(x-0,2)(x+2)
3(-5x²+11x-2)=
3(x-2)(x-0,2)
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(1-5x)(x+2)+(5x-1)(8-2x)=
(x+2-5x²-10x)+(40x-10x²-8+2x)=
x+2-5x²-10x+40x-10x²-8+2x=
-15x²+33x-6=
-3(5x²-11x+2)
5x²-11x+2=0
Δ=121-40=81
√Δ=9
x₁=(11-9)/(10)=2/10=0,2
x₂=(11+9)/(10)=20/10=2
-3(5x²-11x+2)= -3(x-0,2)(x+2)
3(-5x²+11x-2)=
3(x-2)(x-0,2)