Peluang
banyak angka = 20
r= 3
banyak cara pengambilan 3 angka dari 20 --> n(S) = 20C3 = 1.140
susunan 3 angka berurutan = A
A= (1,2,3), (2,3,4) ,...,(18,19, 20) --> n(A) = 18
P(A) = 18/1140 = 3/190
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Peluang
banyak angka = 20
r= 3
banyak cara pengambilan 3 angka dari 20 --> n(S) = 20C3 = 1.140
susunan 3 angka berurutan = A
A= (1,2,3), (2,3,4) ,...,(18,19, 20) --> n(A) = 18
P(A) = 18/1140 = 3/190