Odpowiedź:
cos 120= cos (180-60)=- cos 60=-1/2
tg 135= tg (180-45)=-tg 45=-1
sin 135= sin ( 180-45)= sin 45=√2/2
tg 120= tg (180-60)=-tg 60=-√3
cos 135=cos (180-45)=-cos 45=-√2/2
a)
(-1/2-1)*√2/2= -3/2*√2/2=-3√2/4
b)
(-√3-√2/2)(-√3-√2/2)= (-√3-√2/2)²= 3+ √6+ 1/2= 3,5+√6
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Verified answer
Odpowiedź:
cos 120= cos (180-60)=- cos 60=-1/2
tg 135= tg (180-45)=-tg 45=-1
sin 135= sin ( 180-45)= sin 45=√2/2
tg 120= tg (180-60)=-tg 60=-√3
cos 135=cos (180-45)=-cos 45=-√2/2
a)
(-1/2-1)*√2/2= -3/2*√2/2=-3√2/4
b)
(-√3-√2/2)(-√3-√2/2)= (-√3-√2/2)²= 3+ √6+ 1/2= 3,5+√6
Szczegółowe wyjaśnienie: