Daję naj ; ) Oblicz procent masowy pierwiastków chemicznych w propanolu .
wzór: C3H7OH
masa: 12+12+12+7+17=60g
C: 36/60 x 100%=60%
H: 8/60 x 100%=13,3%
O: 16/60 x 100%=26,7%
mC3H7OH=36+8+16=60u
%C=(36/60)*100% = 60%
%H=(8/60)*100% = 13,3%
%O=(16/60)*100% = 26,7%
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wzór: C3H7OH
masa: 12+12+12+7+17=60g
C: 36/60 x 100%=60%
H: 8/60 x 100%=13,3%
O: 16/60 x 100%=26,7%
mC3H7OH=36+8+16=60u
%C=(36/60)*100% = 60%
%H=(8/60)*100% = 13,3%
%O=(16/60)*100% = 26,7%