Dados los puntos A.(-2,0,1 ) B.(4,-4,2 ) C.(-3,1,0 ) D.(-2,1,5 ) CALCULAR PARA _ _ ab , cd *Repres.... Question from @moranangelina96

October 2018 1 23 Report

Dados los puntos
A.(-2,0,1 )
B.(4,-4,2 )
C.(-3,1,0 )
D.(-2,1,5 )

CALCULAR PARA _ _
ab , cd
*Representar segmento
*Calcular Distancia
* Calcular y Ubicar Punto Medio

#Me Urge porfavor lo mas pronto posible es para
mañana lunes

Akenaton Distancia:

$dAB= \sqrt{(X2-X1)^{2} +(Y2-Y1)^{2}+(Z2-Z1)^{2}}$

Donde: X1 = -2; Y1 = 0; Z1 = 1
X2 = 4 ; Y2 = -4 ; Z2 = 2

$d= \sqrt{(4-(-2))^{2} +(-4-0)^{2}+(2-1)^{2}}$

$d= \sqrt{(6))^{2} +(-4)^{2}+(1)^{2}}$

$d= \sqrt{36 + 16+ 1}$

$d= \sqrt{53} =7.2801$

Xm = [X1 + X2]/2 = [-2 + 4]/2 = 2/2 = 1

Ym = [Y1 + Y2]/2 = [0 + (-4)]/2 = -4/2 = -2

Zm = [Z1 + Z2]/2 = [1 + 2]/2 = 3/2 = 1.5

Punto Medio: (1,-2,1.5)

AB: Distancia = 7.28; Punto Medio: (1,-2,1.5)

Distancia: CD: C.(-3,1,0 ) D.(-2,1,5 )

$dCD= \sqrt{(X2-X1)^{2} +(Y2-Y1)^{2}+(Z2-Z1)^{2}}$

Donde: X1 = -3; Y1 = 1; Z1 = 0: X2 = -2; Y2 = 1; Z2 = 5

$dCD= \sqrt{(-2-(-3))^{2} +(1-1)^{2}+(5-0)^{2}}$

$dCD= \sqrt{(1)^{2} +(0)^{2}+(5)^{2}}$

$dCD= \sqrt{1+25}$

$dCD= \sqrt{26}=5.099$

Punto medio:

Xm = [X1 + X2]/2 = [-3+(-2))]/2 = -5/2 = -2.5

Ym = [Y1 + Y2]/2 = [1+1]/2 = 2/2 = 1

Zm = [Z1 + Z2]/2 = [0 + 5]/2 = 5/2 = 2.5

Punto Medio: (-2.5,1,2.5)

CD: Distancia = 5.099; Punto Medio: (-2.5,1,2.5)

La segunda imagen los puntos son C y D

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