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(6x-3)^2 ≤ (x+17)^2
(6x-3)^2 - (x+17)^2 ≤ 0
(6x-3+x+17)(6x-3-x-17) ≤ 0
(7x+14)(5x-20) ≤ 0
(x+2)(x-4) ≤ 0
x ∈ [-2;4]
Mínimo valor = -2
Máximo valor = 4
Suma = 2