Respuesta:
[tex]x =96cm, y = 50cm ;[/tex] la correcta es la opción a )
Explicación paso a paso:
Por Pitágoras:
[tex]x^{2} = (104cm)^{2} -(40cm)^{2}[/tex]
[tex]x^{2} = 10816cm^{2} -1600cm^{2} = 9216cm^{2}[/tex]
[tex]x = \sqrt{9216cm^{2} }[/tex]
[tex]x = 96cm[/tex]
[tex]y^{2} = (40cm)^{2} +(126cm-96cm)^{2} = (40cm)^{2} +(30cm)^{2} = 1600cm^{2} +900cm^{2}[/tex]
[tex]y^{2} = 2500cm^{2}[/tex]
[tex]y = \sqrt{2500cm^{2} }[/tex]
[tex]y = 50cm[/tex]
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Respuesta:
[tex]x =96cm, y = 50cm ;[/tex] la correcta es la opción a )
Explicación paso a paso:
Por Pitágoras:
[tex]x^{2} = (104cm)^{2} -(40cm)^{2}[/tex]
[tex]x^{2} = 10816cm^{2} -1600cm^{2} = 9216cm^{2}[/tex]
[tex]x = \sqrt{9216cm^{2} }[/tex]
[tex]x = 96cm[/tex]
[tex]y^{2} = (40cm)^{2} +(126cm-96cm)^{2} = (40cm)^{2} +(30cm)^{2} = 1600cm^{2} +900cm^{2}[/tex]
[tex]y^{2} = 2500cm^{2}[/tex]
[tex]y = \sqrt{2500cm^{2} }[/tex]
[tex]y = 50cm[/tex]