a = 3, b = 5, c= 11, d = 7, Por lo tanto a*c = 3*11 =33
Tenemos que: 9/a=15/b=33/c=21/d, entonces
9b = 15a ⇒ a = 9/15*b = 0.6*b
33b = 15c ⇒ c = 33/15*b = 2.2*b
33d = 21c ⇒ 33d = 21*(2.2*b) = 46.2*b
⇒ d = 46.2/33*b = 1.4*b
Luego: c-a+b-d=6, sustituyendo:
2.2b - 0.6b + b - 1.4b = 6
1.2b = 6
b= 6/1.2 = 5
Sustituimos:
a = 0.6*5= 3
b = 5
c= 2.2*5 = 11
d= 1.4*5= 7
Por lo tanto a*c = 3*11 =33
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Verified answer
a = 3, b = 5, c= 11, d = 7, Por lo tanto a*c = 3*11 =33
Tenemos que: 9/a=15/b=33/c=21/d, entonces
9b = 15a ⇒ a = 9/15*b = 0.6*b
33b = 15c ⇒ c = 33/15*b = 2.2*b
33d = 21c ⇒ 33d = 21*(2.2*b) = 46.2*b
⇒ d = 46.2/33*b = 1.4*b
Luego: c-a+b-d=6, sustituyendo:
2.2b - 0.6b + b - 1.4b = 6
1.2b = 6
b= 6/1.2 = 5
Sustituimos:
a = 0.6*5= 3
b = 5
c= 2.2*5 = 11
d= 1.4*5= 7
Por lo tanto a*c = 3*11 =33