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100 kg 1,2 kilomola
SO3 + H2O ---> H2SO4
1 mol 1 mol
1 mol SO3 - 1 mol H2SO4
x mol SO3 - 1200 mol H2SO4
-----------------------------------
x= 1200 mol SO3
M(masa molowa SO3)= 3*16g/mol + 32 g/mol=80 g/mol
m=n*M=1200 mol * 80 g/mol = 96000 g = 96 kg
Odp. Aby uzyskać 1,2 kilomola H2SO4 potrzeba 96 kg SO3, tak więc 100 kg wystarczy.