¿Cuantos metros mide por lado un cuadrado cuya área es de 100 metros cuadrados y que dos de sus lados miden x+5? URGEEEE
yexs
![Hola~~\mathbb{CUATITA} \\ \\ Vamos~ilustrar~haciendo~um~cuadrado: \\ \\ ~~~~~~~~~~~~~~~~~~a~\boxed{\Bigg| ~100m\²\Bigg|}~~--\ \textgreater \ \acute{a}rea~\boxed{A=a\² }\\~~~~~~~~~~~~~~~~~~~~~~~~~~ a\\ \\ Nos~indica~que: \\ \\ ~\underbrace{dos~de~sus~lados}_{a+a} ~\underbrace{midem}_{=}~\underbrace{[x+5]}_{x+5} \\ \\ Entonces: \\ \\](https://tex.z-dn.net/?f=Hola%7E%7E%5Cmathbb%7BCUATITA%7D++%5C%5C++%5C%5C+Vamos%7Eilustrar%7Ehaciendo%7Eum%7Ecuadrado%3A+%5C%5C++%5C%5C+%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7Ea%7E%5Cboxed%7B%5CBigg%7C+%7E100m%5C%C2%B2%5CBigg%7C%7D%7E%7E--%5C+%5Ctextgreater+%5C+%5Cacute%7Ba%7Drea%7E%5Cboxed%7BA%3Da%5C%C2%B2+%7D%5C%5C%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E+a%5C%5C+%5C%5C+Nos%7Eindica%7Eque%3A+%5C%5C++%5C%5C+%7E%5Cunderbrace%7Bdos%7Ede%7Esus%7Elados%7D_%7Ba%2Ba%7D+%7E%5Cunderbrace%7Bmidem%7D_%7B%3D%7D%7E%5Cunderbrace%7B%5Bx%2B5%5D%7D_%7Bx%2B5%7D+%5C%5C++%5C%5C+Entonces%3A+%5C%5C++%5C%5C+ "Hola~~\mathbb{CUATITA} \\ \\ Vamos~ilustrar~haciendo~um~cuadrado: \\ \\ ~~~~~~~~~~~~~~~~~~a~\boxed{\Bigg| ~100m\²\Bigg|}~~--\ \textgreater \ \acute{a}rea~\boxed{A=a\² }\\~~~~~~~~~~~~~~~~~~~~~~~~~~ a\\ \\ Nos~indica~que: \\ \\ ~\underbrace{dos~de~sus~lados}_{a+a} ~\underbrace{midem}_{=}~\underbrace{[x+5]}_{x+5} \\ \\ Entonces: \\ \\")
![a+a=x+5 \\ \\ 2a=x+5 \\ \\ \boxed{a= \frac{x+5}{2}}~~----\ \textgreater \ (I) \\ \\ \mathbb{iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii} \\ Se~sabe~que: \\ \\ A= a^{2} ~~--\ \textgreater \ reemplazamos~[A=100~~, ~~a= \frac{x+5}{2} ~~],vea: \\ \\ 100=\bigg( \frac{x+5}{2} \bigg)^{2} ~~--\ \textgreater \ por~propiedad~[ n^{2} =m=\ \textgreater \ n= \sqrt{m}~] \\ \\](https://tex.z-dn.net/?f=a%2Ba%3Dx%2B5+%5C%5C++%5C%5C+2a%3Dx%2B5+%5C%5C++%5C%5C+%5Cboxed%7Ba%3D+%5Cfrac%7Bx%2B5%7D%7B2%7D%7D%7E%7E----%5C+%5Ctextgreater+%5C+%28I%29+%5C%5C++%5C%5C+%5Cmathbb%7Biiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii%7D++%5C%5C+Se%7Esabe%7Eque%3A+%5C%5C++%5C%5C+A%3D+a%5E%7B2%7D+%7E%7E--%5C+%5Ctextgreater+%5C+reemplazamos%7E%5BA%3D100%7E%7E%2C+%7E%7Ea%3D+%5Cfrac%7Bx%2B5%7D%7B2%7D+%7E%7E%5D%2Cvea%3A+%5C%5C++%5C%5C+100%3D%5Cbigg%28+%5Cfrac%7Bx%2B5%7D%7B2%7D++%5Cbigg%29%5E%7B2%7D+%7E%7E--%5C+%5Ctextgreater+%5C+por%7Epropiedad%7E%5B+n%5E%7B2%7D+%3Dm%3D%5C+%5Ctextgreater+%5C+n%3D+%5Csqrt%7Bm%7D%7E%5D+%5C%5C++%5C%5C++ "a+a=x+5 \\ \\ 2a=x+5 \\ \\ \boxed{a= \frac{x+5}{2}}~~----\ \textgreater \ (I) \\ \\ \mathbb{iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii} \\ Se~sabe~que: \\ \\ A= a^{2} ~~--\ \textgreater \ reemplazamos~[A=100~~, ~~a= \frac{x+5}{2} ~~],vea: \\ \\ 100=\bigg( \frac{x+5}{2} \bigg)^{2} ~~--\ \textgreater \ por~propiedad~[ n^{2} =m=\ \textgreater \ n= \sqrt{m}~] \\ \\")
![\bigg( \frac{x+5}{2} \bigg)= \sqrt{100} \\ \\ \frac{x+5}{2} =10 \\ \\ x+5=20 \\ \\ x=20-5 \\ \\ \boxed{x=15}~~--\ \textgreater \ como~tenemos~valor~de~(x)~reemplazamos~em~(I) \\ \\ a= \frac{x+5}{2} ~~--\ \textgreater \ tenemos~que~[x=15], reemplazando \\ \\ a= \frac{15+5}{2} \\ \\](https://tex.z-dn.net/?f=%5Cbigg%28+%5Cfrac%7Bx%2B5%7D%7B2%7D+%5Cbigg%29%3D+%5Csqrt%7B100%7D+++%5C%5C++%5C%5C++%5Cfrac%7Bx%2B5%7D%7B2%7D+%3D10+%5C%5C++%5C%5C+x%2B5%3D20+%5C%5C++%5C%5C+x%3D20-5+%5C%5C++%5C%5C+%5Cboxed%7Bx%3D15%7D%7E%7E--%5C+%5Ctextgreater+%5C+como%7Etenemos%7Evalor%7Ede%7E%28x%29%7Ereemplazamos%7Eem%7E%28I%29+%5C%5C++%5C%5C++a%3D+%5Cfrac%7Bx%2B5%7D%7B2%7D+%7E%7E--%5C+%5Ctextgreater+%5C+tenemos%7Eque%7E%5Bx%3D15%5D%2C+reemplazando+%5C%5C++%5C%5C+a%3D+%5Cfrac%7B15%2B5%7D%7B2%7D++%5C%5C++%5C%5C+ "\bigg( \frac{x+5}{2} \bigg)= \sqrt{100} \\ \\ \frac{x+5}{2} =10 \\ \\ x+5=20 \\ \\ x=20-5 \\ \\ \boxed{x=15}~~--\ \textgreater \ como~tenemos~valor~de~(x)~reemplazamos~em~(I) \\ \\ a= \frac{x+5}{2} ~~--\ \textgreater \ tenemos~que~[x=15], reemplazando \\ \\ a= \frac{15+5}{2} \\ \\")
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gracias!! :D JEJE NOSE COMO AGRADACERTE POR TODO LO QUE ME HAS AYUDADO.. GRACIAS ;)
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