¿Cuántos globos de goma de 6 litros de capacidad pueden llenarse en CN. Con el he procedente de un cilindro que contiene 250 litros de gas a 68 °F y a 5 atm de presión?
snorye
V = 250 L ºc = ºf -32 / 1.8 ºC = 68 - 32 / 1.8 ºC = 20 T1 = 20 + 273 = 293 K P1 = 5 atm. CN: T2 = 273 K y P2 = 1 atm
P1 x V1 = P2 x V2 ``````````` ```````````` T1 T2
V2 = T2 x P1 x V1 ````````````````` P2 x T1
V2 = 273 K x 5 Atm x 250 L ``````````````````````````````` 1 atm x 293 K
ºc = ºf -32 / 1.8
ºC = 68 - 32 / 1.8
ºC = 20
T1 = 20 + 273 = 293 K
P1 = 5 atm.
CN: T2 = 273 K y P2 = 1 atm
P1 x V1 = P2 x V2
``````````` ````````````
T1 T2
V2 = T2 x P1 x V1
`````````````````
P2 x T1
V2 = 273 K x 5 Atm x 250 L
```````````````````````````````
1 atm x 293 K
V2 = 1164,68 L
nº de GLOBOS = 1164,68 L
```````````````
6 L
Nº de globos = 194