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Entonces:
39g K ------- 1mol ------- avogadro
2g K --------- x moles
x= 2 x 1 / 39= 0,05 moles de K
39g K ------ 1mol ------ 6,022.10^23 átomos de K
2g ------------------------- x átomos de K
x= 2 x 6,022.10^23 / 39= 3,088.10^22 átomos de K