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x²- 3x -4=0
x1,x2= -b +-√b²-4ac/2a donde x² =a | - 3x=b | -4 = c
y quedaria como 1=a, -3=b, -4=c
entonces decimos:
x1,x2 = -(-3)+-√(-3)²-4(1)(-4)/2(1)
una vez sustituido, resolvemos
x1,x2= 3+-√9+16/2
x1,x2= 3+-√25/2
entonces decimos
x1 = 3+√25/2 =4
x2 = 3-√25/2 = -1