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㏑(yˣ) = ㏑(xˣ)
x㏑(y) = x㏑(x)
si x ≠ 0 entonces
㏑(y) = ㏑(x)
Derivando
y'/y = 1/x
y' = y/x
pero quien es y ?
㏑(y) = ㏑(x)
Aplicando base euler a la ecuación, queda:
y = x
Por tanto
y' = x/x
y' = 1
∴ La derivada es 1