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16x - 130 = - 2x²
2x² + 16x - 130 = 0 Simplificas sacas mitad
x² + 8x - 65 = 0 Factorizas trinomio de la forma x² + bx + c
(x + 13)(x - 5) = 0 Tiene como solución dos raices reales
x + 13 = 0
x = - 13
o
x - 5 = 0
x = 5
Solución.
(- 13 , 5)
2x² + 16x - 130 = 0 divido entre 2
x² + 8x - 65 = 0
x +13
x -5
13x - 5x = 8x
(x + 13)(x - 5) = 0
x + 13 = 0 x - 5 = 0
x = -13 x = - 5
CS = (- 13 , 5)