cot (A + B) = 1/(tan (A + B) = 1 : ((tan A + tan B) / (1 - tan A . tan B)) = (1 - tan A tan B) / (tan A + tan B) = (1 - 1/cot A . 1/cot B) / (1/cot A + 1/cot B) = ((cot A . cot B - 1)/(cot A . cot B)) : (cot B + cot A)/(cot A . cot B) = (cot A . cot B - 1) / (cot A + cot B)
Verified answer
Bab TrigonometriMatematika SMA Kelas X
cot (A + B) = 1/(tan (A + B)
= 1 : ((tan A + tan B) / (1 - tan A . tan B))
= (1 - tan A tan B) / (tan A + tan B)
= (1 - 1/cot A . 1/cot B) / (1/cot A + 1/cot B)
= ((cot A . cot B - 1)/(cot A . cot B)) : (cot B + cot A)/(cot A . cot B)
= (cot A . cot B - 1) / (cot A + cot B)
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