cos (a - b) = 1/2 √3 cos a cos b + sin a sin b = 1/2 √3 1/2 + sin a sin b = 1/2 √3 sin a sin b = 1/2 (√3 - 1)
•• cos (a - b) / cos (a + b) = 1/2 √3 / cos a cos b - sin a sin b = 1/2 √3 / (1/2 - 1/2 (√3 - 1)) = 1/2 √3 / (1 - 1/2 √3) = 1/2 √3 × 2/(2 - √3) = √3 / (2 - √3) = √3 (2 + √3) /(2² - (√3)²) = 3 + 2√3
Verified answer
TriGonoMetRicos (a - b) = 1/2 √3
cos a cos b + sin a sin b = 1/2 √3
1/2 + sin a sin b = 1/2 √3
sin a sin b = 1/2 (√3 - 1)
••
cos (a - b) / cos (a + b)
= 1/2 √3 / cos a cos b - sin a sin b
= 1/2 √3 / (1/2 - 1/2 (√3 - 1))
= 1/2 √3 / (1 - 1/2 √3)
= 1/2 √3 × 2/(2 - √3)
= √3 / (2 - √3)
= √3 (2 + √3) /(2² - (√3)²)
= 3 + 2√3