Carilah dy/dx dari : a. y = sin 1/x b. y = cos x^2 c. y = 5/sin x d. y = 2/cos x
Ghinashodaa. y = sin x/x dy/dx = cos x (x) - 1(Sinx) x² = x cox - sin x x² b. y = cos x^2 = (cos x)² dy/dx = 2cosx(-sinx) = -2sinxcosx = -Sin2x c. y = 5/sin x dy/dx = 0(sinx) - 5cosx Sin²x = -5cosx/sin²x = (-5cosx/sinx)(1/sinx) = -5Cotx.Cscx d. y = 2/cos x dy/dx = -2Sinx/cos²x = -2TanxSecx Jadikan aku yang terbaik ya :)
dy/dx = cos x (x) - 1(Sinx)
x²
= x cox - sin x
x²
b. y = cos x^2 = (cos x)²
dy/dx = 2cosx(-sinx)
= -2sinxcosx
= -Sin2x
c. y = 5/sin x
dy/dx = 0(sinx) - 5cosx
Sin²x
= -5cosx/sin²x
= (-5cosx/sinx)(1/sinx)
= -5Cotx.Cscx
d. y = 2/cos x
dy/dx = -2Sinx/cos²x
= -2TanxSecx
Jadikan aku yang terbaik ya :)