sin A + sin B = 2 sin 1/2(A+B) cos 1/2(A-B) sin A - sin B = 2 cos 1/2(A+B) sin 1/2(A-B) cos A + cos B = 2 cos 1/2 (A+B) cos 1/2 (A-B) cos A - cos B = - 2 sin 1/2 (A+B) sin 1/2 (A-B)
a) (sin 7a - sin 5a) / (cos 7a + cos 5a) = tan a = sin 7a - sin 5a/ cos 7a + cos 5a = (2 cos 1/2 (7a +5a) sin 1/2 (7a -5a) / (2 cos 1/2(7a+5a) cos 1/2(7a-5a)) = (2 cos 6a sin a )/(2 cos 6a cos a) = sin a/cos a = tan a
b) cos 6a - cos 4a / sin 6a - sin 4a = = (-2 sin 1/2(6a+4a) sin1/2(6a-4a)) / (2 cos 1/2(6a+4a) cos 1/2(6a-4a)) = (- 2 sin 5a sin a) / (2 cos 5a cos a) = - tan 5a . tan a
c) sin a + sin 3a / cos a + cos 3a = = 2 sin 1/2(3a+a) cos 1/2(3a-a) / 2 cos 1/2 (3a + a) cos (3a - a) = ( 2 sin 2a cos a) / (2 cos 2a cos a) = sin 2a/ cos 2a = tan 2a
d) sin 3a - sin a / cos a + cos 3a = = 2 cos 1/2(3a+a) sin 1/2(3a -a) / 2 cos 1/2 (3a+a) cos 1/2 (3a-a) = 2 cos 2a sin a / 2 cos 2a cos a = sin a/ cos a = tan a
Verified answer
Jawabsin A + sin B = 2 sin 1/2(A+B) cos 1/2(A-B)
sin A - sin B = 2 cos 1/2(A+B) sin 1/2(A-B)
cos A + cos B = 2 cos 1/2 (A+B) cos 1/2 (A-B)
cos A - cos B = - 2 sin 1/2 (A+B) sin 1/2 (A-B)
a) (sin 7a - sin 5a) / (cos 7a + cos 5a) = tan a
= sin 7a - sin 5a/ cos 7a + cos 5a
= (2 cos 1/2 (7a +5a) sin 1/2 (7a -5a) / (2 cos 1/2(7a+5a) cos 1/2(7a-5a))
= (2 cos 6a sin a )/(2 cos 6a cos a)
= sin a/cos a
= tan a
b) cos 6a - cos 4a / sin 6a - sin 4a =
= (-2 sin 1/2(6a+4a) sin1/2(6a-4a)) / (2 cos 1/2(6a+4a) cos 1/2(6a-4a))
= (- 2 sin 5a sin a) / (2 cos 5a cos a)
= - tan 5a . tan a
c) sin a + sin 3a / cos a + cos 3a =
= 2 sin 1/2(3a+a) cos 1/2(3a-a) / 2 cos 1/2 (3a + a) cos (3a - a)
= ( 2 sin 2a cos a) / (2 cos 2a cos a)
= sin 2a/ cos 2a
= tan 2a
d) sin 3a - sin a / cos a + cos 3a =
= 2 cos 1/2(3a+a) sin 1/2(3a -a) / 2 cos 1/2 (3a+a) cos 1/2 (3a-a)
= 2 cos 2a sin a / 2 cos 2a cos a
= sin a/ cos a
= tan a