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y√53 = 125
sacamos logaritmo a ambos lados:
log y√53 = log 125
regla del producto de logs, por lo tanto:
log y + log √53 = log 125
regla de potencia de logs:
log y + (1/2) log 53 = log 125
log y = log 125 - (1/2) log 53
2 log y = 2 log 125 - log 53
2 log y = log 125^2 - log 53
2 log y = log (125^2/53)
log y = (1/2) log (125^2/53)
log y = log √(125^2/53)
y = exp^√(125^2/53)