Question

Con su debido procedimiento

Answer 1

Fórmula !!!! loga (a^x)=x !!!!!

a)) log2 (1024:256)= log2 (4)= log (2^2)= 2;

b)) log5 (625•125)= log5 (5^4• 5^3)= log5 ( [5] ^4+3)= log5 (5^7)= 7;

c)) log7 (343•49)= log7 (7^3• 7^2)= log7 (7^ [3+2])= log7 (7^5)= 5;

d)) log4 (16^15)= log4 ( [4^2]^15]= log4 (4^{2•15})= log4 (4^30)= 30;