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2 < (t + 3)/2 < 3 --->Multiplicamos por 2 la inecuación
2(2) < 2(t+3)/2 < 3(2) --->Simplificamos 2
4 < t + 3 < 6 --->Restamos 3 a la inecuación
4 - 3 < t + 3 - 3 < 6 - 3
1 < t < 3
El tiempo de espera solo sera de 1 hora exactamente