Respuesta:
x=3;y=4
Explicación paso a paso:
[tex]2x+y=10\\y_{1} =-2x+10\\x-2y=-5\\y_{2} =\frac{x}{2} +\frac{5}{2} \\y_{2}=y_{1} igualacion\\-2x+10=\frac{x}{2} +\frac{5}{2} \\2x+\frac{x}{2}= -\frac{5}{2} +10\\\frac{5x}{2}=\frac{15}{2}\\x=\frac{15}{5} \\x=3\\si\\y_{1} =-2x+10\\y_{1} =-2(3)+10\\y_{1} =-6+10\\y_{1} =4[/tex]
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Respuesta:
x=3;y=4
Explicación paso a paso:
[tex]2x+y=10\\y_{1} =-2x+10\\x-2y=-5\\y_{2} =\frac{x}{2} +\frac{5}{2} \\y_{2}=y_{1} igualacion\\-2x+10=\frac{x}{2} +\frac{5}{2} \\2x+\frac{x}{2}= -\frac{5}{2} +10\\\frac{5x}{2}=\frac{15}{2}\\x=\frac{15}{5} \\x=3\\si\\y_{1} =-2x+10\\y_{1} =-2(3)+10\\y_{1} =-6+10\\y_{1} =4[/tex]