Question

co dalej BARDZO PROSZE O POMOC W ROZWIAZANIU TEGO ZADANIA ;(

Answer 1

r=promień=5cm

h=wysokosc=8,2cm

l=tworzaca=√[5²+8,2²]=√92,24=√9224/100=2√2306/10=√2306/5

Pp=πr²=π×5²=25π

v=⅓Pph=⅓×25π×8,2=205π/3=68⅓π cm³

Pb=πrl=π×5×√2306/5=√2306π

Pc=25π+√2306π=π(25+√2306)cm²

 

lub tak;

l=√92,24

Pb=π×5×√92,24=5√92,24π

Pc=5√92,24π+25π=5π(√92,24+5)cm²

Answer 2

r= 5 cm

h= 8m2 cm

l=?

 

P=Pp+Pb

V= 1/3*Pp*h

 

Pp= πr²

Pp= 25πcm²

Pb= πrl

l²=r²+h²

l²=25+67,24=92,24

l=√92,24

Pb=5√92,24π

Pc= 25π+5√92,24π=5π(5+√92,24)cm²

 

V=1/3*25π*8,2=68 1/3 π cm³