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c(KMnO₄) = 0,00045 g/cm³ = 0,00045/158,03 mol/cm³ = 2,85*10⁻⁶ mol/cm³
n(KMnO₄) = 30 * 2,85*10⁻⁶ = 8,54*10⁻⁵ mol
n(Fe²⁺) = 5*n(KMnO₄) = 5*8,54*10⁻⁵ = 0,00043 mol (w 25 cm³); czyli 0,0043 mol w 250 cm³
m(Fe) = n * M = 0,0043 mol * 55,85 g/mol = 0,24 g