Question

Oblicz stezenie molowe 20% roztworu HNO3 o gestosci 1,12g/cm3??

Answer 1

Mm HNO3 = 1+14+3*16 = 63g
ms = 20 g
mr = 100g

Vr = mr/d = 100 / 1,12 = 83 cm3 = 0,083 dm3
n = ms/Mm = 20/63 = 0,32 mol

Cm = n/V = 0,32/0,083 = 3,9 mol/dm3