1.Oblicz stężenie molowe 13,45% roztworu Na2CO3, którego gęstość wynosi d=1,14 g/cm3
Cp= 13,45%
dr= 1,14 g/cm3
M= 106 g/mol
Cm= Cp * 1000dr/ M* 100%
Cm= 13,45% * 1140 g*dm^-3/ 106 g/mol * 100%
Cm= 1,45 mol/dm3
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Cp= 13,45%
dr= 1,14 g/cm3
M= 106 g/mol
Cm= Cp * 1000dr/ M* 100%
Cm= 13,45% * 1140 g*dm^-3/ 106 g/mol * 100%
Cm= 1,45 mol/dm3