Ile wynosi ciężar bryłki żelaza o objętości 200cm^3. Gęstość żelaza wynosi 7900kg/cm^3. prosze o pomoc hellllp
m=V*q
m=200cm^3 * 7900kg/cm^3
m=1580000kg
Fc=m*g
Fc=1580000kg * 10m/s^2
Fc=15800000N=15800kN
V=200 cm³
ρ=7900 kg/cm³
m=?
m=V*ρ
m=200*7900
m=1580000 kg=1580 t
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m=V*q
m=200cm^3 * 7900kg/cm^3
m=1580000kg
Fc=m*g
Fc=1580000kg * 10m/s^2
Fc=15800000N=15800kN
V=200 cm³
ρ=7900 kg/cm³
m=?
m=V*ρ
m=200*7900
m=1580000 kg=1580 t