Question

1. Ile gramów substancji znajduje sie w 50 cm szesciennych 20% roztworu o gestosci d= 1,2 g/cm szescienny

Answer 1

Ms=?
v=50 cm3
Cp=20%
d=1,2 g/cm3

d=mr/v
mr=d*v
mr=50*1,2=60 g

ms=Cp*mr/100%
ms=20%*60g/100%
ms= 12 g

Answer 2

D=m/v
m=d*v
m=60g

Cp= ms100%/mr
ms= (cp*mr)/100%
ms= 20%*60/100%
ms=12g