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= 1/3 log 15 + 1/3 log 15
= 1/3 (log 3 + log 5) + 1/3 (log 3 + log 5) = 1/3.b + 1/3.log 5 + 1/3.b + 1/3.log 5
= 2/3 a + 2/3 b
mungkin petunjuknya log 5
2. [1/a log bc + a log a] + [1/b log ca + b log b] + [1/c log ab + c log c]
= 1/a log abc + 1/b log abc + 1/c log abc
= abc log a + abc log b + abc log c = abc log abc = 1