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γ = 3 α
γ Alumunium = 3 .2,4 .10⁻⁵ ; γ Minyak = 2 . 10⁻⁴
VAl = γ . ΔT + V₀
= 3 . 2,4 .10⁻⁵ . 70 + 5
= 50,4 . 10⁻⁴ + 5000
V Myk = γ . ΔT + V₀
= 2 . 10⁻⁴ . 70 + 5000
Minyak yang tumpah =
|Val - V Myk|
= |50,4 . 10⁻⁵ + 5000 - (140 . 10⁻⁴ + 5000)|
= |-1349,6 . 10⁻⁵|
= 0,013496 cm³