Ciąg (an) jest określony wzorem an=3n-7. Oblicz średnią arytmetyczną wyrazów a2, a6, a8, a10
an = 3n-7
a₂ = 3*2-7 = -1
a₆=3*6-7 = 11
a₈= 3*8-7=17
a₁₀=3*10-7=23
śr = (-1+11+17+23)/4 = 50/4 = 12,5
a2 = 3*2-7 = -1
a6=3*6-7 = 11
a8= 3*8-7=17
a10=3*10-7=23
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an = 3n-7
a₂ = 3*2-7 = -1
a₆=3*6-7 = 11
a₈= 3*8-7=17
a₁₀=3*10-7=23
śr = (-1+11+17+23)/4 = 50/4 = 12,5
an = 3n-7
a2 = 3*2-7 = -1
a6=3*6-7 = 11
a8= 3*8-7=17
a10=3*10-7=23