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T1 = 27 C
T2 = 327 C ; temp. topnienia Pb
delta T = 327-27 = 300 C
cw = 130 J/Kg*C
ct = 25000 J/kg
a:
Q1 = m *cw *delta T
Q 1 = 5 kg *130 J/kg*C*300 C
Q1 = 195000 J = 195 kJ
b:
Q2= m*ct
Q2 = 5 kg* 25000 J/kg
Q2 = 125000 J = 125 kJ
ile razy większa :
Q1/Q2 = 195kJ/125 kJ
Q1/Q2 = 1,56