Carilah titik potong terhadap sumbu x dan sumbu y dari: 1) 2x-y = -8 2) 3y = -x + 5 3) -x = 12 - 2y 4) 6x - 10 = -4y
arini14012002
1) 2x-y = -8. titik potong terhadap sumbu x → (4,0) misal sumbu y = 0 maka 2x-y = -8 2x-0 = -8 2x = -8 x = -8/2 = 4 titik potong terhadap sumbu y ↔(0,8) x harus 0→x = 0 maka 2x-y = -8 2(0)-y = -8 -y = -8 = ↔ y = 8
misal sumbu y = 0 maka 2x-y = -8
2x-0 = -8
2x = -8
x = -8/2 = 4
titik potong terhadap sumbu y ↔(0,8)
x harus 0→x = 0 maka 2x-y = -8
2(0)-y = -8
-y = -8 = ↔ y = 8