Carilah nilai dari a.) sin 120° b.) cos 300° c.) tan 150° d.) sec 210° e.) 330° f.) cosec 120° beserta cara penyelesaiannya ?
zulfachan
A. sin 120 = 1/2 akar 3 b. cos300 = 1/2 c. tan150 = - 1/3 akar 3 d. sec210 = - 1/cos30 = - 1/ akar 3/2 = - 2 akar 3/3 f. cosec 120 = 1/sin60 = 1/akar 3/2 = 2 akar 3/3
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zulfachan
a. sin 120 = sin (180 - 60) = sin 601/2 akar 3
b. cos300 = cos (270 + 30 ) = sin 30 = 1/2
c. tan150 =-tan ( 180 - 30 ) = - tan 30 = - 1/3 akar 3
d. sec210 = 1/cos210 =1/cos (180+30) = 1/-cos30 = - 1/ akar 3/2 = - 2 akar 3/3
f. cosec 120 = 1/sin120 = 1/sin (180-60) = 1/sin 60 = 1/akar 3/2 = 2 akar 3/3
b. cos300 = 1/2
c. tan150 = - 1/3 akar 3
d. sec210 = - 1/cos30 = - 1/ akar 3/2 = - 2 akar 3/3
f. cosec 120 = 1/sin60 = 1/akar 3/2 = 2 akar 3/3
b. 1/2
c. 1/3 akar 3