Carilah luas permukaan balok dengan panjang sisi berikut. a. p = 25cm, L = 12cm, t = 10cm b. p = 5dm, L = 45cm, t = 5dm c. p = 3,2m, L = 18cm, t = 65cm
gegezzz
A. Lp= 4(p*l)+4(p*t)+4(t*l) =4(25*12)+4(25*10)+4(12*10) =4(300)+4(250)+4(120) =1200+1000+480=2680cm² b. Lp=4(5*45)+4(5*5)+4(45*5) =4(225)+4(25)+4(225) =900+100+900=1900dm² c. Lp=4(3,2*18)+4(3,2*65)+4(18*65) =4(57,6)+4(208)+4(1170) =5742,4cm²
2. 270 + 250 + 120
2. 640
1280 cm^2
b. 2 (50.45 + 50.50 + 45.50)
2 (2250 + 2500 + 2250)
2 ( 7000)
14.000 cm^2
c. 2 (32.18 + 32.65 + 18.65)
2 (576 + 2080 + 1170 )
2 (3826)
7652 cm^2
=4(25*12)+4(25*10)+4(12*10)
=4(300)+4(250)+4(120)
=1200+1000+480=2680cm²
b. Lp=4(5*45)+4(5*5)+4(45*5)
=4(225)+4(25)+4(225)
=900+100+900=1900dm²
c. Lp=4(3,2*18)+4(3,2*65)+4(18*65)
=4(57,6)+4(208)+4(1170)
=5742,4cm²