" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Verified answer
Integral tertentu1.
₀⁴ ∫ √x dx = ₀⁴∫ x¹/² dx = ²/₃ [ x³/²]⁴₀
= 2/3 (4³/² - 0³/²)
= 2/3 ( 8)
= 16/3
2. ₁³∫ 5 - x dx = [5x - 1/2 x²}³₁
= 5(3-1) - 1/2(3²-1²)
= 5(2) - 1/2(9-1)
= 10 - 4
= 6
3. ₀⁸∫ x² - 1 dx = [1/3 x³ - x]⁸₀
= 1/3(8³-0³) - (3-0)
= 1/3(512) - 3
= (512 -9)/3 = 503/3 = 167 ²/₃
4.
ₐᵇ∫ dx/x² = ₐᵇ∫x⁻² dx = - [1/x]ᵇᵃ
= - (1/b - 1/a)
= - (a-b)/(ab)