Question

Cari keliling dan luas. pake cara

Answer 1

PS = √PT² + TS²
PS = √(25-16)² + (24/2)²
PS = √9² + 12²
PS = √81 + 144
PS = √225
PS = 15 cm

RS = √TS² + TR²
RS = √12² + 16²
RS = √144 + 256
RS = √400
RS = 20 cm

Keliling = QP + PS + SR + RQ
            = 15 + 15 + 20 + 20
            = 70 cm

d₁ = PR
d₂ = QS

Luas = 1/2 x d₁ x d₂
        = 1/2 x 25 x 24
        = 300 cm²

Answer 2

PT = PR-RT = 25-16 = 9 cm
QT = 1/2.SQ = 1/2.24 = 12 cm
maka:
PQ = PS = akar dr PT²+QT²
= akar dr 9²+12²
= akar dr 81+144
= √225
= 15 cm

QR = RS = akar dr QT²+RT²
= akar dr 12²+16²
= akar dr 144+256
= √400
= 20 cm

jadi, K = PQ+PS+QR+RS
= 15+15+20+20
= 70 cm

dan

L = 1/2.d1.d2
= 1/2.SQ.PR
= 1/2.24.25
= 12.25
= 300 cm²