Question

cari jawaban yg paling tepat dan benar pakai cara nya ​

Answer 1

Jawaban:

y = x² - 3x + 2

T1 pencerminan terhadap sumbu x

T2 dilatasi [O, 3]

[x',y'] = T2 O T1 [x, y]

\begin{gathered} \left[\begin{array}{ccc}x'\\y'\end{array}\right]\,= \left[\begin{array}{ccc}3&0\\0&3\end{array}\right] \left[\begin{array}{ccc}1&0\\0&-1\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right]\end{gathered}

[

x

′

y

′

]=[

3

0

0

3

][

1

0

0

−1

][

x

y

]

\begin{gathered}\left[\begin{array}{ccc}x'\\y'\end{array}\right]\,= \left[\begin{array}{ccc}3&0\\0&-3\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right]\end{gathered}

[

x

′

y

′

]=[

3

0

0

−3

][

x

y

]

x' = 3x → x = 1/3 x'

y' = - 3y → y= - 1/3 y'

subs ke y = x² - 3x + 2

(-1/3 y') = (1/3 x')² - 3(-1/3 x') + 2

- 1/3 y = 1/9x² + x + 2 ......kalikan -3

y = - 1/3 x² - 3x - 18

maaf jika salah