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f'(x) = 12x²-12x+8
f'(1) = 8←gradien titik singgung
persamaan garis singgung:
y-y' = 8x - 8
8x-y+y'-8 = 0
px-y+p+1 = 0
maka p = 8 dan y' = 8+8+1
y' = 17
titik singgung di (1,17)
f(x) = ∫12x²-12x+8 dx
f(x) = 4x³-6x²+8x+ C
tentukan nilai C:
f(1) = 4x³-6x²+8x+ C
17 = 4-6+8+C
C = 11
f(x) = 4x³-6x²+8x+11
f(2) = 32-24+16+11
= 35....................opsi C