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x+y=1 ⇒ x=1-y
x+5y=5
(1-y)+5y=5
1+4y=5
4y=4
y=1
maka, x+y=1
x+1=1
x=0
x + 5y = 5 … persamaan (2)
Penyelesaian:
Dari pers.(2) didapat : x = 5 – 5y … persamaan (3)
Kemudian substitusikan pers.(3) ke pers.(1) :
x + y = 1
⇔ 5 – 5y + y = 1
⇔ 5 – 4y = 1
⇔ – 4y = 1 – 5
⇔ – 4y = – 4
⇔ y = 1
Nilai y = 1 lalu substitusikan y ke pers (3)
x = 5 – 5y
x = 5 – 5(1)
x = 5 – 5
x = 0
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