Luas selimut kerucut yang keliling alasnya 75,36 cm,tinggi 16 cm,dan pendekatan \pi 3,14 adalah.. a.602,88 cm² c. 1.205.76 cm² b. 753,6 cm² d. 9.034,2 cm²
kautsarmus
K=2πr r=K÷2π r=75,36÷2.3,14 r=75,36÷6,28 r=12 cm
s²=t²+r² s²=16²+12² s²=256+144 s=√400 s=20 cm
Ls=πrs Ls=3,14. 12. 20 Ls=753,6 cm²
Jawaban B
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junitanjung
Keliling alas =2πr 75.36=2x3.14r 75.36=6.28r r=75.36/6.28 r=12
r=K÷2π
r=75,36÷2.3,14
r=75,36÷6,28
r=12 cm
s²=t²+r²
s²=16²+12²
s²=256+144
s=√400
s=20 cm
Ls=πrs
Ls=3,14. 12. 20
Ls=753,6 cm²
Jawaban B
75.36=2x3.14r
75.36=6.28r
r=75.36/6.28
r=12
s=√r²+t²=√12²+16²=√144+256=√400=20
Ls=πrs=3.14x12x20=753.6cm²(b)